The Post Your Thoughts of the Moment Thread 2

[KefkaticFanatic]

Oh, so I got 30 more Google Wave invites so PM me your email if you want one.

[universe-X]

Do you know why their even sending you all this?

[Harvest]

Oh, so I got 30 more Google Wave invites so PM me your email if you want one.

I never got the one you sent me.

[Dude]

I got mine >_>

[Harvest]

oh wait I did get it, it just took a long time and I missed it.

[Magus Darkwind]

A nice thing.
I'm gonna prove that 0,99999999999999..... is exactly the same as 1.

Let's say x = 0,99999999999999......
Then 10 x = 9,9999999999999999....
10 x - x = 9 x
9x = (10 x - x) = 9,999999999999999.... - 0,9999999999999........ = 9
Then x = 1

Great, right?

Ok, good ideas, always good to see some creativity.  

Now, for starters, you mean .999999999999..., now we will work assuming that.

Now then, 10 x .9999 = 9.9990

10x - x = 9x

9.999-.9999= 8.9991

9x = 8.9991, divide that by 9 and you get

x = .9999 - works like a charm.

Now what is different with this situation? It is a repeating decimal, that is ok, it means you put a 8.999...1

Have fun with math.

[Magus Darkwind]

Now, I am going to prove, 1=2

Let's say a = b
Now in a few steps I will prove to you that 1 = 2
a = b
a^2 (squared)= ab: multiply both sides by a
a^2 - b^2 = ab - b^2 : subtract b squared from both sides
(a - b)(a + b) = b(a - b): factor
a + b = b : divide (a - b) from both sides
b + b = b : substitute b for a because they're equal
2b = b : add like terms
2 = 1 : divide both sides by b

[Harvest]

Actually, you can't do math in this thread.

[Seeker]

Now, for starters, you mean .999999999999..., now we will work assuming that.

Minor annoyance: that is standard notation elsewhere, such as Europe IIRC, not a typo.

Now then, 10 x .9999 = 9.9990

10 * .9999 = 9.999, yes. However, 10 * .9999.... = 9.9999... The nines don't end. Moving a decimal point isn't going to force an ending.

[universe-X]

^^ @Magus, i like your thoughts, but your last two steps were wrong.

2b = b

You can still combine like terms across equations and inequalities.
Take, for example,

2x•47 + 6 - y = 5x
and you wanna make a function out of it, using y as the range and x as the domain.

First:
2x•47 + 6 - y = 5x

Subtract 2x from both sides

47 + 6 -y = 5x

Combine constants:
53 - y = 5x

Subtract 53 from both sides:

-y = 5x - 53

Divide both sides by -1 (optional)

y = -5x + 53

^^ there's your answer. now substitute x with 1 and y with 1

1 = 58

^^ WTF?

so, for

2b = b

You're still combining like terms, and I guess, substituting the "empty" side with zero (0, you gotta love that number). So when you combine like terms... again, you get:

2b = b â†'â†"
(subtract b from both sides [focusing on the left side])

1b=...

b = __

b = 0

Keep dreaming.

[KefkaticFanatic]

What the fuck, get your own thread.

[Seeker]

First:
2x•47 + 6 - y = 5x

Subtract 2x from both sides

47 + 6 -y = 5x

!?!

[universe-X]

Wow . . . that wasn't embarrassing at all

But my main point is that getting 2 to equal 1 is like getting chocolate to taste like ham.

[Seeker]

Now I want to soak a couple Hershey's kisses in ham juice and see what happens.

[universe-X]

Ham and chocolate . . .









Tasty.